Joule-Thomson effect
The Joule-Thomson effect is also known as the Joule-Kelvin effect.
Joule-Thomson coefficient
The Joule-Thomson coefficient is given by
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu_{\mathrm JT} = \left. \frac{\partial T}{\partial p} \right\vert_H}
where T is the temperature, p is the pressure and H is the enthalpy.
In terms of heat capacities one has
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu_{\mathrm JT} C_V = -\left. \frac{\partial E}{\partial V} \right\vert_T }
and
- Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \mu _{\mathrm {J} T}C_{p}=-\left.{\frac {\partial H}{\partial p}}\right\vert _{T}}
In terms of the second virial coefficient at zero pressure one has
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mu_{\mathrm JT}\vert_{p=0} = ^0\!\!\phi = B_2(T) -T \frac{dB_2(T)}{dT}}