Heat capacity: Difference between revisions

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:<math>C_V = \left.\frac{\delta Q}{\partial T} \right\vert_V = \left. \frac{\partial U}{\partial T} \right\vert_V </math>
:<math>C_V = \left.\frac{\delta Q}{\partial T} \right\vert_V = \left. \frac{\partial U}{\partial T} \right\vert_V </math>


where ''U'' is the [[internal energy]], ''T'' is the temperature, and  ''V'' is the volume.
where ''U'' is the [[internal energy]], ''T'' is the [[temperature]], and  ''V'' is the volume.
 
==At constant pressure==
==At constant pressure==
:<math>C_p = \left.\frac{\delta Q}{\partial T} \right\vert_p = \left. \frac{\partial U}{\partial T} \right\vert_p + p \left.\frac{\partial V}{\partial T} \right\vert_p</math>
:<math>C_p = \left.\frac{\delta Q}{\partial T} \right\vert_p = \left. \frac{\partial U}{\partial T} \right\vert_p + p \left.\frac{\partial V}{\partial T} \right\vert_p</math>

Revision as of 15:17, 29 January 2008

From the first law of thermodynamics we have

δQ=dU+pdV

the heat capacity is given by

C=δQ∂T

At constant volume

CV=δQ∂T|V=∂U∂T|V

where U is the internal energy, T is the temperature, and V is the volume.

At constant pressure

Cp=δQ∂T|p=∂U∂T|p+p∂V∂T|p

where p is the pressure.

We have

Cp−CV=(p+∂U∂V|T)∂V∂T|p