Heat capacity: Difference between revisions

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:<math>C = \frac{\delta Q}{\partial T}</math>
:<math>C = \frac{\delta Q}{\partial T}</math>
==At constant volume==
==At constant volume==
:<math>C_v = \left.\frac{\delta Q}{\partial T} \right\vert_V = \left. \frac{\partial U}{\partial T} \right\vert_V </math>
:<math>C_V = \left.\frac{\delta Q}{\partial T} \right\vert_V = \left. \frac{\partial U}{\partial T} \right\vert_V </math>


where ''U'' is the [[internal energy]], ''T'' is the temperature, and  ''V'' is the volume.
where ''U'' is the [[internal energy]], ''T'' is the temperature, and  ''V'' is the volume.
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where ''p'' is the [[pressure]].
where ''p'' is the [[pressure]].
We have
:<math>C_p -C_V = \left( p + \left. \frac{\partial U}{\partial V} \right\vert_T \right) \left. \frac{\partial V}{\partial T} \right\vert_p</math>
[[category: classical thermodynamics]]
[[category: classical thermodynamics]]

Revision as of 11:10, 21 June 2007

From the first law of thermodynamics we have

δQ=dU+pdV

the heat capacity is given by

C=δQ∂T

At constant volume

CV=δQ∂T|V=∂U∂T|V

where U is the internal energy, T is the temperature, and V is the volume.

At constant pressure

Cp=δQ∂T|p=∂U∂T|p+p∂V∂T|p

where p is the pressure.

We have

Cp−CV=(p+∂U∂V|T)∂V∂T|p