Logarithmic oscillator thermostat: Difference between revisions

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{{Stub-general}}
The '''Logarithmic oscillator''' <ref>[http://dx.doi.org/10.1103/PhysRevLett.108.250601 Michele Campisi, Fei Zhan, Peter Talkner, and Peter Hänggi "Logarithmic Oscillators: Ideal Hamiltonian Thermostats", Physical Review Letters '''108''' 250601 (2012)]</ref> in one dimension is given by (Eq. 2):
The '''Logarithmic oscillator thermostat''' <ref>[http://dx.doi.org/10.1103/PhysRevLett.108.250601 Michele Campisi, Fei Zhan, Peter Talkner, and Peter Hänggi "Logarithmic Oscillators: Ideal Hamiltonian Thermostats", Physical Review Letters '''108''' 250601 (2012)]</ref>.
 
:<math>H = \frac{P^2}{2M}+ T \ln \frac{\vert X \vert}{b}</math>
 
where <math>X</math> is the position of the logarithmic oscillator, <math>P</math> is its linear momentum, and <math>M</math> represents its mass. <math>T</math> is the desired [[temperature]] of the thermostat, and <math>b > 0</math> sets a length-scale.
==As a thermostat==
From the [[Virial theorem]]
 
:<math>\left\langle X\frac{\partial H}{\partial X} \right\rangle  = \left\langle P\frac{\partial H}{\partial P} \right\rangle  </math>
 
one obtains
 
:<math>T = \left\langle \frac{P^2}{M} \right\rangle  </math>.
 
This implies that all expectation values of the trajectories correspond to the very same temperature of the thermostat, irrespective of the [[internal energy]].
In other words,
 
:<math>\frac{\partial T}{\partial U} = 0</math>
 
this implies that the [[heat capacity]] becomes
 
:<math>C_V := \left. \frac{\partial U}{\partial T} \right\vert_V  = \infty </math>
 
Having an infinite heat capacity is an ideal feature for a thermostat.
==Practical applicability==
==Practical applicability==
<ref>[http://arxiv.org/abs/1205.3478 Marc Meléndez Schofield "On the logarithmic oscillator as a thermostat", arXiv:1205.3478v1 (cond-mat.stat-mech) 15 May (2012)]</ref>
<ref>[http://arxiv.org/abs/1205.3478 Marc Meléndez Schofield "On the logarithmic oscillator as a thermostat", arXiv:1205.3478v1 (cond-mat.stat-mech) 15 May (2012)]</ref>
<ref>[http://dx.doi.org/10.1103/PhysRevLett.110.028901 Marc Meléndez, Wm. G. Hoover, and Pep Español "Comment on “Logarithmic Oscillators: Ideal Hamiltonian Thermostats”", Physical Review Letters '''110''' 028901 (2013)]</ref>
<ref>[http://dx.doi.org/10.1103/PhysRevLett.110.028901 Marc Meléndez, Wm. G. Hoover, and Pep Español "Comment on “Logarithmic Oscillators: Ideal Hamiltonian Thermostats”", Physical Review Letters '''110''' 028901 (2013)]</ref>
<ref>[http://dx.doi.org/10.1103/PhysRevLett.110.028902 Michele Campisi, Fei Zhan, Peter Talkner, and Peter Hänggi "Campisi et al. Reply", Physical Review Letters '''110''' 028902 (2013)]</ref>
<ref>[http://dx.doi.org/10.1103/PhysRevE.89.021301 Daniel Sponseller and Estela Blaisten-Barojas "Failure of logarithmic oscillators to serve as a thermostat for small atomic clusters", Physical Review E '''89''' 021301(R) (2014)]</ref>
==References==
==References==
<references/>
<references/>

Revision as of 17:13, 16 April 2015

The Logarithmic oscillator [1] in one dimension is given by (Eq. 2):

H=P22M+Tln|X|b

where X is the position of the logarithmic oscillator, P is its linear momentum, and M represents its mass. T is the desired temperature of the thermostat, and b>0 sets a length-scale.

As a thermostat

From the Virial theorem

⟨X∂H∂X⟩=⟨P∂H∂P⟩

one obtains

T=⟨P2M⟩.

This implies that all expectation values of the trajectories correspond to the very same temperature of the thermostat, irrespective of the internal energy. In other words,

∂T∂U=0

this implies that the heat capacity becomes

CV:=∂U∂T|V=∞

Having an infinite heat capacity is an ideal feature for a thermostat.

Practical applicability

[2] [3] [4] [5]

References

Related reading