Integration of the kinetic degrees of freedom
Considering a system of
identical particles, with total energy
given by:

where the first term on the right hand side is the kinetic energy, whereas the second one is
the potential energy (function of the position coordinates)
Let
be the total energy of the system.
The probability,
of a given position configuratiom
, with potential energy
can be written as:
; (Eq. 1)
where
stands for the 3N momenta, and

The Integral in the right hand side of Eq. 1 corresponds to the surface of a 3N-dimensional hyper-sphere of radious
;
Therefore:
![{\displaystyle \Pi \left(X^{3N}|E\right)\propto \left[E-U(X^{3N})\right]^{(3N-1)/2}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/6d1348dde456f0c5c5b3411e85a773590b000dd3)
See Ref 1 for an example of this method
References
- N. G. Almarza and E. Enciso "Critical behavior of ionic solids" Phys. Rev. E 64, 042501 (2001) [4 pages ]
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