Semi-grand ensembles: Difference between revisions

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: <math> d \left( \beta A \right) = E d \beta - (\beta p) d V +  \beta \mu_1 d N + \beta (\mu_2-\mu_1) d N_2. </math>
: <math> d \left( \beta A \right) = E d \beta - (\beta p) d V +  \beta \mu_1 d N + \beta (\mu_2-\mu_1) d N_2; </math>


TO BE CONTINUED
Or:
 
: <math> d \left( \beta A \right) = E d \beta - (\beta p) d V +  \beta \mu_1 d N + \beta \mu_{21} d N_2; </math>
 
where <math> \mu_{21} = \mu_2 - \mu_1 </math>. Now considering the thermodynamical potentia: <math> \beta A - N_2 \beta \mu_{21} </math>
 
TO BE CONTINUED ... SOON

Revision as of 15:03, 5 March 2007

General Features

Semi-grand ensembles are used in Monte Carlo simulation of mixtures.

In this ensembles the total number of molecules is fixed, but the composition can change.

Canonical Ensemble: fixed volume, temperature and number(s) of molecules

We will consider a binary system;. In the Canonical Ensemble, the differential equation energy for the Helmholtz energy function can be written as:

d(βA)=Edβ−(βp)dV+∑i=12(βμi)dNi,

where:

  • A is the Helmholtz energy function
  • β≡1/kBT
  • kB is the Boltzmann constant
  • T is the absolute temperature
  • E is the internal energy
  • p is the pressure
  • μi is the chemical potential of the species "i"
  • Ni is the number of molecules of the species "i"

Semi-grand ensemble at fixed volume and temperature

Consider now that we want to consider a system with fixed total number of particles, N

N=N1+N2;

but the composition can change, from the thermodynamics we can apply a Legendre's transform [HAVE TO CHECK ACCURACY] to the differential equation written above in terms of A(T,V,N1,N2).

  1. Consider the change (N1,N2)→(N,N2) i.e.: N1=N−N2


d(βA)=Edβ−(βp)dV+βμ1dN−βμ1dN2+βμ2dN2;


d(βA)=Edβ−(βp)dV+βμ1dN+β(μ2−μ1)dN2;

Or:

d(βA)=Edβ−(βp)dV+βμ1dN+βμ21dN2;

where μ21=μ2−μ1. Now considering the thermodynamical potentia: βA−N2βμ21

TO BE CONTINUED ... SOON